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View Full Version : Unhandless access violation with glTexImage2D



Exempt
08-18-2013, 10:54 AM
edit: I got this working with the code below... although I'd still really like to know why the other doesn't work...

unsigned int loadTexture(const char* name)
{
SDL_Surface* img = IMG_Load(name);
SDL_PixelFormat form={NULL,32,4,0,0,0,0,8,8,8,8,0xff000000,0x00ff0 000,0x0000ff00,0x000000ff,0,255};
SDL_Surface* img2 = SDL_ConvertSurface(img,&form,SDL_SWSURFACE);
unsigned int texture;

glGenTextures(1,&texture);
glBindTexture(GL_TEXTURE_2D,texture);
glTexImage2D(GL_TEXTURE_2D, 0, GL_RGBA, img2->w, img2->h, 0, GL_RGBA, GL_UNSIGNED_INT_8_8_8_8, img2->pixels);
glTexParameteri(GL_TEXTURE_2D,GL_TEXTURE_MAG_FILTE R,GL_LINEAR);
glTexParameteri(GL_TEXTURE_2D,GL_TEXTURE_MIN_FILTE R,GL_LINEAR);
glBindTexture(GL_TEXTURE_2D, 0);
SDL_FreeSurface(img);
SDL_FreeSurface(img2);
return texture;
}

I'm a bit lost as to how this is failing to load a 32bit RGBA .bmp image into a texture. I'm getting a unhandled access violation so I assume it's going out of bounds but I'm not sure why it would be.


unsigned int loadTexture(const char* filename)
{
SDL_Surface* img = IMG_Load(filename);
unsigned int id;

glGenTextures(1, &id);
glBindTexture(GL_TEXTURE_2D, id);
glTexImage2D(GL_TEXTURE_2D, 0, GL_RGBA, img->w, img->h, 0, GL_RGBA, GL_UNSIGNED_INT_8_8_8_8, img->pixels);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MAG_FILTER, GL_LINEAR);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_LINEAR);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_WRAP_S, GL_CLAMP);
glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_WRAP_T, GL_CLAMP);
glTexParameteri(GL_TEXTURE_2D, GL_GENERATE_MIPMAP, GL_TRUE);
glBindBuffer(GL_TEXTURE_2D, 0);

SDL_FreeSurface(img);
return id;
}