Dan M

05-15-2010, 01:08 PM

So assuming I don't have access to the code that sets the near clipping plane is there a way of getting this value out of the GL?

View Full Version : Finding out the near clipping plane

Dan M

05-15-2010, 01:08 PM

So assuming I don't have access to the code that sets the near clipping plane is there a way of getting this value out of the GL?

Rosario Leonardi

05-15-2010, 02:54 PM

For standard projection matrix you have something like that

http://www.opengl.org/sdk/docs/man/xhtml/gluPerspective.xml

a = projectionM[10]

b = projectionM[14]

With some simple math...

<div class="ubbcode-block"><div class="ubbcode-header">Click to reveal.. <input type="button" class="form-button" value="Show me!" onclick="toggle_spoiler(this, 'Yikes, my eyes!', 'Show me!')" />]<div style="display: none;">[1] a = (n+f)/(n-f)

[2] b = 2nf/(n-f)

[1] became (if n != f)

(n-f)a = n+f => an-af = n+f => an-n = af+f => n = f(a+1)/(a-1) (if a != 1)

now you can isolate n in [2]

b(n-f) = 2nf

bn-2nf = bf

n = bf/(b-2f)

so

bf/(b-2f) = f(a+1)/(a-1)

if(f != 0)

b/(b-2f) = (a+1)/(a-1)

and here is simple, with a little of patience you get

f=b/(a+1)

n = f(a+1)/(a-1)

so

n = b/(a-1)

So, at the end you get[/QUOTE]</div>

f = b/(a+1)

n = b/(a-1)

if(a!=1, a!=-1, f!=n, b!=2f)

far plane = f

near plane = n

http://www.opengl.org/sdk/docs/man/xhtml/gluPerspective.xml

a = projectionM[10]

b = projectionM[14]

With some simple math...

<div class="ubbcode-block"><div class="ubbcode-header">Click to reveal.. <input type="button" class="form-button" value="Show me!" onclick="toggle_spoiler(this, 'Yikes, my eyes!', 'Show me!')" />]<div style="display: none;">[1] a = (n+f)/(n-f)

[2] b = 2nf/(n-f)

[1] became (if n != f)

(n-f)a = n+f => an-af = n+f => an-n = af+f => n = f(a+1)/(a-1) (if a != 1)

now you can isolate n in [2]

b(n-f) = 2nf

bn-2nf = bf

n = bf/(b-2f)

so

bf/(b-2f) = f(a+1)/(a-1)

if(f != 0)

b/(b-2f) = (a+1)/(a-1)

and here is simple, with a little of patience you get

f=b/(a+1)

n = f(a+1)/(a-1)

so

n = b/(a-1)

So, at the end you get[/QUOTE]</div>

f = b/(a+1)

n = b/(a-1)

if(a!=1, a!=-1, f!=n, b!=2f)

far plane = f

near plane = n

Dan M

05-16-2010, 08:21 AM

Many thanks, that is a fantastic reply :)

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