kasemodz

11-29-2009, 08:10 AM

I'm working on this robot project, that outputs some continuous values while the robot is moving. Currently, my code to draw these values are such below.

//Displacement of Robot

glColor3f(1.0f, 0.0f, 0.0f);

glLineWidth (3);

glBegin(GL_LINE_STRIP);

glVertex2f(0, 0); // origin of the line

glVertex2f(Y_VALUE, X_VALUE); // ending point of the

glEnd( ); line

So, while the robot is moving, it is constantly giving me new y-value and x-value, and I'm trying to develop a code where the current position of the robot is displayed on the computer screen. Thus, I need to figure out some type of loop that keeps creating a new glVertex2f function for every new x-value and y-value. For example

glBegin(GL_LINE_STRIP);

glVertex2f(0, 0); // origin of the line

glVertex2f(Y_VALUE_1, X_VALUE_1);

glVertex2f(Y_VALUE_2, X_VALUE_2);

glVertex2f(Y_VALUE_3, X_VALUE_3);

................................

glVertex2f(Y_VALUE_N, X_VALUE_N);

glEnd( );

If I can figure this out, then the lines will be connected from the origin till the last x and y value. I will greatly appreciate any help provided. Thanks.

//Displacement of Robot

glColor3f(1.0f, 0.0f, 0.0f);

glLineWidth (3);

glBegin(GL_LINE_STRIP);

glVertex2f(0, 0); // origin of the line

glVertex2f(Y_VALUE, X_VALUE); // ending point of the

glEnd( ); line

So, while the robot is moving, it is constantly giving me new y-value and x-value, and I'm trying to develop a code where the current position of the robot is displayed on the computer screen. Thus, I need to figure out some type of loop that keeps creating a new glVertex2f function for every new x-value and y-value. For example

glBegin(GL_LINE_STRIP);

glVertex2f(0, 0); // origin of the line

glVertex2f(Y_VALUE_1, X_VALUE_1);

glVertex2f(Y_VALUE_2, X_VALUE_2);

glVertex2f(Y_VALUE_3, X_VALUE_3);

................................

glVertex2f(Y_VALUE_N, X_VALUE_N);

glEnd( );

If I can figure this out, then the lines will be connected from the origin till the last x and y value. I will greatly appreciate any help provided. Thanks.