BoSoft

04-20-2004, 06:59 AM

Hi,

When I looked at the physical approach of Nvidia's paper, I was very confused about one part of the equation:

sqr( I - n²(1-(N.I)²) )

N and I are vectors.

How can you take the square root of a vector,

and how can you subtract a scalar from a vector?

AFAIK it is not possible.

Should there be a 1 instead of the first I ?

-FA

When I looked at the physical approach of Nvidia's paper, I was very confused about one part of the equation:

sqr( I - n²(1-(N.I)²) )

N and I are vectors.

How can you take the square root of a vector,

and how can you subtract a scalar from a vector?

AFAIK it is not possible.

Should there be a 1 instead of the first I ?

-FA