Hi all,

for some days i try to get this done - and i am ashamed that i cant figure it out on my own..
i am doind a simple ground-hight detection for my game.
The ground is a mesh of triangles.
I allready can test in with triangle i am, but when i coms to calculating the hight of the position on the triangle i fail.
As my point ( player ) is floting abouve the triangle i only need to work with X and Z and than find the propper Y.

here is my function with should find the propper Y. it only works points close to the triangle corners - and i know why ..
but i cant find a way to improve it:
Code :
GLfloat getYbalanced( GLfloat x , GLfloat y, GLfloat z, GLfloat * dreiArray )
{
        // x, y ,z = Point to test
        // dreiArray = array holding points of triangle - some offset in it !
 
    GLfloat result = 0.0f;
    // distance point 1  x + z 
    GLfloat w1 = sqrt( powit( ( dreiArray[0] -  x ) )  +  powit( ( dreiArray[2] - z ) ) );
    // distance point 2  x + z 
    GLfloat w2 = sqrt( powit( ( dreiArray[8] - x ) )   +  powit( ( dreiArray[10] - z ) ) );
    // distance point 3  x + z 
    GLfloat w3 = sqrt( powit( ( dreiArray[16] - x ) )  +  powit( ( dreiArray[18] - z ) ) );
 
    // total distance
    GLfloat w_all = absu( w1 ) + absu( w2 ) + absu( w3 );
 
 
    // get points relativ distance -> as a factor to multiply later
    GLfloat f1 = ( 1.0f / ( w1 / w_all ) ); 
    GLfloat f2 = ( 1.0f / ( w2 / w_all ) ); 
    GLfloat f3 = ( 1.0f / ( w3 / w_all ) ); 
 
 
    result += f1 * dreiArray[1];  // factor for point - multiply with hight of point
    result += f2 * dreiArray[9];  // factor for point - multiply with hight of point
    result += f3 * dreiArray[17]; // factor for point - multiply with hight of point
 
 
    return ( result / ( f1 + f2 + f3 ) ); // result needs to be devided by total factor sum
}

Here a screen, at the corners i am almost fine but in the middel of the triangle the hight is not correct ...
i now what is wrong with the function and why i get the result - but i cant figure a way to improve it..
OPEN IMG LINK: Click image for larger version. 

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thanx for any improvment of my function ... i guess its easy ..

cu
uwi2k2