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Ren
09-17-2007, 05:14 PM
hi guys,
has anyone tried Delaunay triangulate a set of vertices in geometry shader?

I'm trying to do this, but not sure if Geforce 8 series has enough registers and instructions

oc2k1
09-17-2007, 06:13 PM
That is something for that geometry shaders aren't made... You should use the CPU, because there is more flexibility.

Ren
09-19-2007, 05:27 PM
hi ok2k1,
Thanks for advise. But I'm conducting a research to implement delaunay triangulation in GPU

kon
09-29-2007, 04:27 PM
There are examples of computing voronoi diagrams on the gpu and since voronoi and delaunay are dual to each other this could be a way to look for.

Ren
10-01-2007, 02:21 AM
Thanks, I'll look it up

Brolingstanz
10-02-2007, 09:38 AM
Try following the software package links here:
http://www.cs.unc.edu/~dm/

Seems pretty much anything is possible on GPUs nowaydays, even if it's for "offline" stuff. Who would have thunk it?

Ren
10-11-2007, 01:04 AM
I've implemented Delaunay Triangulation in Geforce 8600 GPU, with the Geometry Shader, however, the screen is flicking, where is that?

Is is because of the shader is too complicated? but I still have a 500+ fps. what might be the problem?

ZbuffeR
10-11-2007, 04:25 AM
Hard to say without more details.
Screenshots ?

Ren
10-11-2007, 06:24 AM
Here is a screenshot

http://lhviolinist.com/images/chisel_delaunay.png

The actual model is just a cube, each face consist of two triangles. In the Geometry Shader, I added a vertex in the middle of each triangle and performed a triangulation.

But the screen keeps flicking, and I could see all triangles at once

ZbuffeR
10-11-2007, 06:45 AM
Can you post your geometry shader ?

Lindley
10-11-2007, 09:41 AM
Are you using double-buffering?

Ren
10-11-2007, 10:59 PM
Yeah, I'm using double buffering

My Geometry Shader is quite long, here's the code

#version 120
#extension GL_EXT_geometry_shader4 : enable


#define EPSILON 0.000001

struct ITRIANGLE{
int p1,p2,p3;
};

struct IEDGE{
int p1,p2;
};

struct XYZ{
float x,y,z;
};

bool CircumCircle(float xp,float yp,
float x1,float y1,float x2,float y2,float x3,float y3,
out float xc, out float yc, out float rsqr);

void Triangulate(int nv, XYZ pxyz[10], out ITRIANGLE v[40], out int ntri)
{
bool complete[40];
IEDGE edges[40];
int nedge = 0;
int trimax,emax = 200;
int status = 0;

bool inside;
int i,j,k;
float xp,yp,x1,y1,x2,y2,x3,y3,xc,yc,r;
float xmin,xmax,ymin,ymax,xmid,ymid;
float dx,dy,dmax;

/* Allocate memory for the completeness list, flag for each triangle
trimax = 4 * nv;
if ((complete = malloc(trimax*sizeof(int))) == NULL) {
status = 1;
goto skip;
}*/

/* Allocate memory for the edge list
if ((edges = malloc(emax*(long)sizeof(IEDGE))) == NULL) {
status = 2;
goto skip;
}*/



/*
Find the maximum and minimum vertex bounds.
This is to allow calculation of the bounding triangle
*/
xmin = pxyz[0].x;
ymin = pxyz[0].y;
xmax = xmin;
ymax = ymin;
for (i=1;i<nv;i++) {
if (pxyz[i].x < xmin) xmin = pxyz[i].x;
if (pxyz[i].x > xmax) xmax = pxyz[i].x;
if (pxyz[i].y < ymin) ymin = pxyz[i].y;
if (pxyz[i].y > ymax) ymax = pxyz[i].y;
}
dx = xmax - xmin;
dy = ymax - ymin;
dmax = (dx > dy) ? dx : dy;
xmid = (xmax + xmin) / 2.0;
ymid = (ymax + ymin) / 2.0;

/*
Set up the supertriangle
This is a triangle which encompasses all the sample points.
The supertriangle coordinates are added to the end of the
vertex list. The supertriangle is the first triangle in
the triangle list.
*/
pxyz[nv+0].x = xmid - 20 * dmax;
pxyz[nv+0].y = ymid - dmax;
pxyz[nv+0].z = 0.0;
pxyz[nv+1].x = xmid;
pxyz[nv+1].y = ymid + 20 * dmax;
pxyz[nv+1].z = 0.0;
pxyz[nv+2].x = xmid + 20 * dmax;
pxyz[nv+2].y = ymid - dmax;
pxyz[nv+2].z = 0.0;
v[0].p1 = nv;
v[0].p2 = nv+1;
v[0].p3 = nv+2;
complete[0] = false;
ntri = 1;



/*
Include each point one at a time into the existing mesh
*/
for (i=0;i<nv;i++) {

xp = pxyz[i].x;
yp = pxyz[i].y;
nedge = 0;

/*
Set up the edge buffer.
If the point (xp,yp) lies inside the circumcircle then the
three edges of that triangle are added to the edge buffer
and that triangle is removed.
*/
for (j=0;j<ntri;j++) {
if (complete[j])
continue;
x1 = pxyz[v[j].p1].x;
y1 = pxyz[v[j].p1].y;
x2 = pxyz[v[j].p2].x;
y2 = pxyz[v[j].p2].y;
x3 = pxyz[v[j].p3].x;
y3 = pxyz[v[j].p3].y;
inside = CircumCircle(xp,yp,x1,y1,x2,y2,x3,y3,xc,yc,r);
if (xc < xp &amp;&amp; ((xp-xc)*(xp-xc)) > r)
complete[j] = true;

if (inside) {
/* Check that we haven't exceeded the edge list size
if (nedge+3 >= emax) {
emax += 100;
if ((edges = realloc(edges,emax*(long)sizeof(IEDGE))) == NULL) {
status = 3;
goto skip;
}
}*/

edges[nedge+0].p1 = v[j].p1;
edges[nedge+0].p2 = v[j].p2;
edges[nedge+1].p1 = v[j].p2;
edges[nedge+1].p2 = v[j].p3;
edges[nedge+2].p1 = v[j].p3;
edges[nedge+2].p2 = v[j].p1;
nedge += 3;
v[j] = v[ntri-1];
complete[j] = complete[ntri-1];
ntri--;
j--;
}
}

/*
Tag multiple edges
Note: if all triangles are specified anticlockwise then all
interior edges are opposite pointing in direction.
*/
for (j=0; j<nedge-1; j++) {
for (k=j+1; k<nedge; k++) {
if ((edges[j].p1 == edges[k].p2) &amp;&amp; (edges[j].p2 == edges[k].p1)) {
edges[j].p1 = -1;
edges[j].p2 = -1;
edges[k].p1 = -1;
edges[k].p2 = -1;
}
/* Shouldn't need the following, see note above */
if ((edges[j].p1 == edges[k].p1) &amp;&amp; (edges[j].p2 == edges[k].p2)) {
edges[j].p1 = -1;
edges[j].p2 = -1;
edges[k].p1 = -1;
edges[k].p2 = -1;
}
}
}

/*
Form new triangles for the current point
Skipping over any tagged edges.
All edges are arranged in clockwise order.
*/
for (j=0; j < nedge; j++) {
if (edges[j].p1 < 0 &amp;#0124;&amp;#0124; edges[j].p2 < 0)
continue;
if (ntri >= trimax) {
status = 4;
return;
}
v[ntri].p1 = edges[j].p1;
v[ntri].p2 = edges[j].p2;
v[ntri].p3 = i;
complete[ntri] = false;
ntri++;
}
}

/*
Remove triangles with supertriangle vertices
These are triangles which have a vertex number greater than nv
*/
for (i=0; i < ntri; i++) {
if (v[i].p1 >= nv &amp;#0124;&amp;#0124; v[i].p2 >= nv &amp;#0124;&amp;#0124; v[i].p3 >= nv) {
v[i] = v[ntri - 1];
ntri--;
i--;
}
}
}


bool CircumCircle(float xp,float yp,
float x1,float y1,float x2,float y2,float x3,float y3,
out float xc, out float yc, out float rsqr)
{
float m1,m2,mx1,mx2,my1,my2;
float dx,dy,drsqr;
float fabsy1y2 = abs(y1-y2);
float fabsy2y3 = abs(y2-y3);

/* Check for coincident points */
if (fabsy1y2 < EPSILON &amp;&amp; fabsy2y3 < EPSILON)
return false;

if (fabsy1y2 < EPSILON) {
m2 = - (x3-x2) / (y3-y2);
mx2 = (x2 + x3) / 2.0;
my2 = (y2 + y3) / 2.0;
xc = (x2 + x1) / 2.0;
yc = m2 * (xc - mx2) + my2;
} else if (fabsy2y3 < EPSILON) {
m1 = - (x2-x1) / (y2-y1);
mx1 = (x1 + x2) / 2.0;
my1 = (y1 + y2) / 2.0;
xc = (x3 + x2) / 2.0;
yc = m1 * (xc - mx1) + my1;
} else {
m1 = - (x2-x1) / (y2-y1);
m2 = - (x3-x2) / (y3-y2);
mx1 = (x1 + x2) / 2.0;
mx2 = (x2 + x3) / 2.0;
my1 = (y1 + y2) / 2.0;
my2 = (y2 + y3) / 2.0;
xc = (m1 * mx1 - m2 * mx2 + my2 - my1) / (m1 - m2);
if (fabsy1y2 > fabsy2y3) {
yc = m1 * (xc - mx1) + my1;
} else {
yc = m2 * (xc - mx2) + my2;
}
}

dx = x2 - xc;
dy = y2 - yc;
rsqr = dx*dx + dy*dy;

dx = xp - xc;
dy = yp - yc;
drsqr = dx*dx + dy*dy;

return drsqr <= rsqr;
}

void emitLineLoop(vec4 position0, vec4 position1, vec4 position2, vec4 color){
gl_Position = position0;
gl_FrontColor = color;
EmitVertex();
gl_Position = position1;
gl_FrontColor = color;
EmitVertex();
EndPrimitive();

gl_Position = position1;
gl_FrontColor = color;
EmitVertex();
gl_Position = position2;
gl_FrontColor = color;
EmitVertex();
EndPrimitive();

gl_Position = position2;
gl_FrontColor = color;
EmitVertex();
gl_Position = position0;
gl_FrontColor = color;
EmitVertex();
EndPrimitive();
}


void main(){
int nv = 3;
XYZ pxyz[10];
ITRIANGLE v[40];
int ntri;

pxyz[0].x = gl_PositionIn[0].x;
pxyz[0].y = gl_PositionIn[0].y;
pxyz[0].z = gl_PositionIn[0].z;

pxyz[1].x = gl_PositionIn[1].x;
pxyz[1].y = gl_PositionIn[1].y;
pxyz[1].z = gl_PositionIn[1].z;

pxyz[2].x = gl_PositionIn[2].x;
pxyz[2].y = gl_PositionIn[2].y;
pxyz[2].z = gl_PositionIn[2].z;

pxyz[3].x = mix(pxyz[0].x, mix(pxyz[1].x, pxyz[2].x, 0.5), 0.667);
pxyz[3].y = mix(pxyz[0].y, mix(pxyz[1].y, pxyz[2].y, 0.5), 0.667);
pxyz[3].z = mix(pxyz[0].y, mix(pxyz[1].y, pxyz[2].z, 0.5), 0.667);

pxyz[4].x = mix(pxyz[0].x, mix(pxyz[1].x, pxyz[2].x, 0.3), 0.667);
pxyz[4].y = mix(pxyz[0].y, mix(pxyz[1].y, pxyz[2].y, 0.5), 0.8);
pxyz[4].z = mix(pxyz[0].y, mix(pxyz[1].y, pxyz[2].z, 0.5), 0.4);


pxyz[5].x = mix(pxyz[0].x, mix(pxyz[1].x, pxyz[2].x, 0.7), 0.2);
pxyz[5].y = mix(pxyz[0].y, mix(pxyz[1].y, pxyz[2].y, 0.7), 0.5);
pxyz[5].z = mix(pxyz[0].y, mix(pxyz[1].y, pxyz[2].z, 0.2), 0.6);


Triangulate(4, pxyz, v, ntri);

vec4 position0, position1, position2, color;

for(int i = 0; i < ntri; i++){
position0 = vec4(pxyz[v[i].p1].x, pxyz[v[i].p1].y, pxyz[v[i].p1].z, 1);
position1 = vec4(pxyz[v[i].p2].x, pxyz[v[i].p2].y, pxyz[v[i].p2].z, 1);
position2 = vec4(pxyz[v[i].p3].x, pxyz[v[i].p3].y, pxyz[v[i].p3].z, 1);
if(v[0].p1 == 0){
color = vec4(1, 0, 0, 1);
}else{
color = vec4(0, 1, 0, 1);
}

emitLineLoop(position0, position1, position2, color);
}
}

ZbuffeR
10-12-2007, 12:27 AM
I am not up to date with goemetry shaders, but according to the spec, the type of primitives generated is implicitly is the same as the one use to specify the original geometry.
In you GLSL code there is both emitTriangle() and emitLineLoop() : I would say it is not possible to switch easily without breaking it.

What type of geometry do you specify ? Triangles or lines ?

Ren
10-12-2007, 01:44 AM
Hi ZBufferR,
I didn't use emitTriangle() at all, so I removed it from my Geometry Shader to reduce the confusion.

I've uploaded a short vidio (http://www.lhviolinist.com/images/delaunay.mp4) (taken using my mobile phone) to show how the flicking looks like. In this video, I used mouse to rotate the model around, you can clearly see the flicking

View vidio (http://www.lhviolinist.com/images/delaunay.mp4) (It's a mp4 file, so you should be able to open with Quicktime or other common video players)